week10 modified

docs/Weekly_Group_Assignments/week10.md

@@ -398,7 +398,14 @@ NeoFade(50);
 
 ## measure the power consumption of an output device
 
-- insert a registor of 1 ohm before Neo Pixel LED as a shunt registor
+- insert a registor of 1 ohm before Neo Pixel LED as a shunt registance
+
+Note: What is "shunt resistance"?
+
+![shuntresistor.png](../images/week10/shuntresistor.png)
+
+A shunt resistor is used to measure electric current, alternating or direct. This is done by measuring the voltage drop across the resistor because of its resistor having a very low value of resistance. Shunt resistance should be 1/1000 or less of the total resistance. It is explained in detail [here](https://www.rohm.com/electronics-basics/resistors/shunt-resistors).
+
 - edit code which come to illuminate LED the blightest (parameter is 255 )
 
 ```jsx
@@ -549,13 +556,22 @@ V=IR ∴ I=V/R=139.8/1 =139.8mA [2]
 
 →By doubling the light intensity, the current is almost doubled.
 
-- calcurate Power Consumption
+- calcurate Power Consumption of shunt resistor
+
+P255 = I×V =275.4mV × 275.4mA =  **75.85μW [3]**
+
+P128 = I×V =139.8mV × 139.8 mA = **19.54μW [4]**
+
+calcurate the ratio of [3] to [4] which answer is 75.8 / 19.5 = 3.88
+
+- calcurate Power Consumption of NeoPixels
+
+Though I forgot to measure voltage of between VCC and GND on first neopixel, if it is 5V,...
 
-P255=I*V =275.4mV *275.4mA =  **75.85mW [3]**
+P255 = 5V * 275.4mA = 1377mW =1.3W
 
-P128 = I*V =139.8mV *139.8 mA = **19.54mW [4]**
+P128 = 5V * 139.8mA = 699mw = 0.699W
 
-calcurate the ratio of [3] to [4] which answer is 75.8 / 19.5 =**3.88**
 
 ## What I learned in this week